2=18*b^2

Solution for 2=18*b^2 equation:

2=18b^2

We move all terms to the left:

2-(18b^2)=0

a = -18; b = 0; c = +2;
Δ = b2-4ac
Δ = 02-4·(-18)·2
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-12}{2*-18}=\frac{-12}{-36}
=1/3
$
$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+12}{2*-18}=\frac{12}{-36}
=-1/3
$